{"items": [{"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911313178962", "anchor": "fb-911313178962", "service": "fb", "text": "I think I could figure out whether there's Helmholtz resonance contributing by seeing whether changing the diameter affects the frequencies. If it's a standard \"wavelength determined by length of pipe\" thing then it shouldn't matter much what width the tubes are, while if it's Helmholtz then it would matter a lot.", "timestamp": "1511042116"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872", "anchor": "fb-911316217872", "service": "fb", "text": "It's the same what happens when you put several LC circuits in parallel. Finding an analytical solution might be a pain, but you can usually figure it out numerically.", "timestamp": "1511043188"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872&reply_comment_id=911317126052", "anchor": "fb-911316217872_911317126052", "service": "fb", "text": "→ \"It's the same what happens when you put several LC circuits in parallel.\"
Oh? If I have mouthpiece -> fork -> two parallel tubes of length 1, what frequency should I expect to get? What's the relationship between serial and parallel tubing? How do stopped tubes contribute?", "timestamp": "1511043410"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872&reply_comment_id=911317235832", "anchor": "fb-911316217872_911317235832", "service": "fb", "text": "→ \"Finding an analytical solution might be a pain, but you can usually figure it out numerically.\"
I'm quite happy to solve things numerically if I know what the relationship is, but I'm very confused currently.", "timestamp": "1511043449"}, {"author": "Scott", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872&reply_comment_id=912797434502", "anchor": "fb-911316217872_912797434502", "service": "fb", "text": "→ LC's might work but for this I think it is easier to use transmission lines to model the system. The main issue is one of impedance - determining the driving impedance, transmission line characteristic impedance, and termination impedance. The first two are fixed and the third depends upon whether the non-driven end of the tube is closed or open. All of this depends upon some knowledge of acoustics and how it maps to an electrical analog model, which I am unsure of. Nevertheless, I tested this out with a simple resonator in LTSpice and it behaves as expected for an tube open at both ends when driven by a voltage source (a low impedance pressure wave excitation) and terminated by a short circuit, which represents a low pressure interface to the air at the opposite end of the tube. The standing wave inside the tube is a half wave with low pressure at both ends and maximum volume velocity at each end (electrical current.)", "timestamp": "1511707904"}, {"author": "Scott", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872&reply_comment_id=912867229632", "anchor": "fb-911316217872_912867229632", "service": "fb", "text": "→ I tested this approach out on Jeff's instrument in the video and I can simulate the outcome approximately but I have to make a couple of adjustments which make me concerned. I need to lengthen the first tube by a lot. It could be that the player's mouth all the way to the diaphragm is part of the resonator. I also need to slow down the speed of sound by about 15-20%. It is well known that open tubes behave like they are longer and this tracks with the diameter of the tube, but the amount of correction needed seems more than I was expecting. The predicted frequencies (or rather after \"fitting\" the model to the data) are: 126 Hz, 97 Hz, 103 Hz, 73 Hz. The plot shows the volume velocity (current) for a given excitation at the player's mouth. The 103 Hz note is predicted to be the most difficult to play with the 73 Hz note being slightly easier. I'm also predicting an overtone at 143 Hz and 160 Hz which should be easier to play for those last two notes.", "timestamp": "1511740969"}, {"author": "Scott", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911316217872&reply_comment_id=912867374342", "anchor": "fb-911316217872_912867374342", "service": "fb", "text": "→ test bench:", "timestamp": "1511741006"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052", "anchor": "fb-911319621052", "service": "fb", "text": "Well, I don't remember everything from that EE class, but my first instinct is to treat each branch (measured from your mouth to where it ends) as a separate resonator and then put them in parallel. A closed off tube will contribute half the frequency of an open one, since you're basically doubling it's length. But there's probably more nuance to this than I'm seeing...", "timestamp": "1511044527"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911320978332", "anchor": "fb-911319621052_911320978332", "service": "fb", "text": "→ Whoops, meant to reply to previous comment", "timestamp": "1511044906"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911322280722", "anchor": "fb-911319621052_911322280722", "service": "fb", "text": "→ Let's say we have a tube that makes a 100 Hz note. If we put two of these tubes in series we get 50Hz. Are you predicting that if we put them in parallel we get 200Hz?", "timestamp": "1511045516"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911322784712", "anchor": "fb-911319621052_911322784712", "service": "fb", "text": "→ Because what I see when I try that is that the two tubes in parallel give 100Hz, same as if I have a single tube.", "timestamp": "1511045736"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911323288702", "anchor": "fb-911319621052_911323288702", "service": "fb", "text": "→ No you're right, this is more complicated than I thought", "timestamp": "1511045903"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911323403472", "anchor": "fb-911319621052_911323403472", "service": "fb", "text": "→ When I think about standing waves, the \"identical parallel tubes of length L sound the same note as a single tube of length L\" makes a lot of sense to me.", "timestamp": "1511045994"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911324616042", "anchor": "fb-911319621052_911324616042", "service": "fb", "text": "→ Yeah, it does. So if you have two boxes of different length, and set up independent standing waves in them, and then connect them at one end...", "timestamp": "1511046605"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911324665942", "anchor": "fb-911319621052_911324665942", "service": "fb", "text": "→ There must be a series component, since they're connected...", "timestamp": "1511046647"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911325095082", "anchor": "fb-911319621052_911325095082", "service": "fb", "text": "→ I don't see a pattern when the two parallel forked tubes are different lengths.", "timestamp": "1511046967"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911325135002", "anchor": "fb-911319621052_911325135002", "service": "fb", "text": "→ It's in the expected direction (making it longer makes it lower) but I don't see what's going on.", "timestamp": "1511046984"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911326766732", "anchor": "fb-911319621052_911326766732", "service": "fb", "text": "→ Do you think it makes sense that the shorter tube has more of an effect on the frequency than the longer one? That's what I think, but I'm not sure. (Considering limits of infinitely long or short pipe)", "timestamp": "1511047576"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911319621052&reply_comment_id=911327280702", "anchor": "fb-911319621052_911327280702", "service": "fb", "text": "→ Sort of like opening holes on a clarinet", "timestamp": "1511047943"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542", "anchor": "fb-911322869542", "service": "fb", "text": "Are you certain none of the notes you played are overtones?", "timestamp": "1511045781"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542&reply_comment_id=911323328622", "anchor": "fb-911322869542_911323328622", "service": "fb", "text": "→ Not completely sure, but pretty sure? I couldn't get lower notes for any of them, but I'm also not using a mouthpiece that's well suited for this (just using the end of the tube).", "timestamp": "1511045924"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542&reply_comment_id=911323438402", "anchor": "fb-911322869542_911323438402", "service": "fb", "text": "→ What about higher notes? You could test if the next note up that you can achieve is a full octave higher.", "timestamp": "1511046004"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542&reply_comment_id=911323787702", "anchor": "fb-911322869542_911323787702", "service": "fb", "text": "→ The harmonics are widely spaced, but not the normal predictable single octave. And for some of the harmonics it doesn't matter whether I stop specific openings or not. Gah!", "timestamp": "1511046191"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542&reply_comment_id=911324655962", "anchor": "fb-911322869542_911324655962", "service": "fb", "text": "→ Specifically:
* The harmonic with (i) stopped is ~2x the base frequency of (i) stopped
* The harmonics with (i) unstopped any any combination of (ii), (iii), or nothing stopped are ~2x the frequency of the path out via (i) when considered alone. Increasing or decreasing the 8\" segment, or removing it all together doesn't change this frequency.", "timestamp": "1511046636"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911322869542&reply_comment_id=911327325612", "anchor": "fb-911322869542_911327325612", "service": "fb", "text": "→ Well, so far my \"rearrange numbers until they yield the result I want\" method isn't working, other than finding that (likely coincidentally) dividing the speed of sound in air by the sum of the three airway path lengths is almost exactly 120.", "timestamp": "1511047999"}, {"author": "Elissa", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911323538202", "anchor": "fb-911323538202", "service": "fb", "text": "I truly have no idea, it\u2019s just that this video is interesting and adorable and this whole thing is Aesthetic", "timestamp": "1511046020"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911325144982", "anchor": "fb-911325144982", "service": "fb", "text": "I should build a slide. That would make this much easier to figure out.", "timestamp": "1511047002"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452", "anchor": "fb-911327405452", "service": "fb", "text": "Here's some more data, from a two way fork that's 25.5\" on one side and varying the other:
inches frequency
----- --------
5.5 207
7 202
10.5 172
12.5 166
18.5 145
20 141
25.5 130
26 127
31 117
33 114
38 105
43 96
45 93
51 87
56 80
58 78
64 73", "timestamp": "1511048062"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911329880492", "anchor": "fb-911327405452_911329880492", "service": "fb", "text": "→ With the speed of sound at 13500 in/s, 13500/(2(25.5+x)) seems to match pretty closely.", "timestamp": "1511048548"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911330080092", "anchor": "fb-911327405452_911330080092", "service": "fb", "text": "→ What happens with a \"Y\" shape, where there's a common tube leading up to the fork?", "timestamp": "1511048730"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911330534182", "anchor": "fb-911327405452_911330534182", "service": "fb", "text": "→ Yes, I'm seeing that too:", "timestamp": "1511049041"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911331806632", "anchor": "fb-911327405452_911331806632", "service": "fb", "text": "→ \"What happens with a \"Y\" shape, where there's a common tube leading up to the fork?\"
Ok, tested with a fork of 25\" and 13\", and a varying common tube coming in:
common length frequency
---------------- ----------
1\t171
5\t161
7\t152
13\t132
18\t119
20\t110
26.5\t99
32\t94
34\t84
38\t74
51\t63", "timestamp": "1511049642"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911332934372", "anchor": "fb-911327405452_911332934372", "service": "fb", "text": "→ Modeling this as frequency being what you would get with the left, right, and common lengths added together is pretty good, though not quite right at the low end.", "timestamp": "1511049826"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911333029182", "anchor": "fb-911327405452_911333029182", "service": "fb", "text": "→ Yeah, the more significant the common length, the further the result diverges it seems. Hmm...", "timestamp": "1511049884"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911333263712", "anchor": "fb-911327405452_911333263712", "service": "fb", "text": "→ This seems to be leading towards \"it's mostly the sum of the lengths, though with caveats at long differences\". Except if I have a simple fork, it doesn't change the frequency I get at all. A forked fork of length 13\" gives me 240Hz, while a single one is ~211Hz.", "timestamp": "1511050031"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911327405452&reply_comment_id=911334266702", "anchor": "fb-911327405452_911334266702", "service": "fb", "text": "→ I'm not sure if common length 32\" was an outlier, but it sure makes it look like a function that has to be defined in two pieces.", "timestamp": "1511050694"}, {"author": "Yaron", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911345574042", "anchor": "fb-911345574042", "service": "fb", "text": "Peter Buchak Scott Arf", "timestamp": "1511055325"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911352954252", "anchor": "fb-911352954252", "service": "fb", "text": "All three of these make the same note. They're:
* 2ft - 2ft forked
* 3ft - 1ft forked
* 1.5ft to 1ft - 1ft forked", "timestamp": "1511058173"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911352954252&reply_comment_id=911353303552", "anchor": "fb-911352954252_911353303552", "service": "fb", "text": "→ This one too, but it's very breathy and hard to hold the note:", "timestamp": "1511058238"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911352954252&reply_comment_id=911353353452", "anchor": "fb-911352954252_911353353452", "service": "fb", "text": "→ Pattern so far is that you can just add both sides of a fork, and before the fork it counts more?", "timestamp": "1511058271"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911352954252&reply_comment_id=911354116922", "anchor": "fb-911352954252_911354116922", "service": "fb", "text": "→ These two are the same as each other (120hz)", "timestamp": "1511058745"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911352954252&reply_comment_id=911354251652", "anchor": "fb-911352954252_911354251652", "service": "fb", "text": "→ The ones above were all 125hz, but adding a little more in the form of elbows brings them down to 120", "timestamp": "1511058855"}, {"author": "Mark", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152", "anchor": "fb-911405399152", "service": "fb", "text": "Coupled resonators are weird. Isn't there some phenomenon involving synthesizing a bass note lower than either pipe is capable of by choosing the right pair of two pipes? I think the gist of it is that you will hear a fundamental note (n=1) if you couple a resonator tuned to the octave (n=2) with another resonator tuned to the tenth (n=3).", "timestamp": "1511099526"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911431666512", "anchor": "fb-911405399152_911431666512", "service": "fb", "text": "→ That makes sense, since that's the frequency they have in common: send like 200hz and 300hz can comfortably make either 100hz or 600hz.
On the other hand, I'm predicting that if I couple a pipe of length 2 to a pipe of length 3, while you'd expect to hear the note you'd get from a pipe of length 6, you'll actually get the one from a pipe of length 2.5.", "timestamp": "1511104059"}, {"author": "Mark", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911436711402", "anchor": "fb-911405399152_911436711402", "service": "fb", "text": "→ That's what the summation of the two independent sinusoids would do. But that would be the case for uncoupled oscillators. Not sure what the coupling does, but I think it does not give you two independent sinusoids.", "timestamp": "1511105243"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911438807202", "anchor": "fb-911405399152_911438807202", "service": "fb", "text": "→ Ok, tested it. Here are three pipes:
Straight, length 3
Forked, length 1 and 1.5
Forked, length 2 and 4", "timestamp": "1511105862"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911439825162", "anchor": "fb-911405399152_911439825162", "service": "fb", "text": "→ The first and third play 88hz, the second plays 180hz.", "timestamp": "1511105983"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911439974862", "anchor": "fb-911405399152_911439974862", "service": "fb", "text": "→ If we were synthesizing a low bass note, we would have expected to be able to get 88hz (90hz) out of the second, but I can't.", "timestamp": "1511106050"}, {"author": "Mark", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911405399152&reply_comment_id=911440893022", "anchor": "fb-911405399152_911440893022", "service": "fb", "text": "→ Fun: Type sin(2k)+sin(3k) into wolfam alpha.
http://m.wolframalpha.com", "timestamp": "1511106452"}, {"author": "Mac", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911435873082", "anchor": "fb-911435873082", "service": "fb", "text": "Thot 1: diameter to length matters. Pipes work well when d<<l.
Thot 2: resonances are phenomena of opportunity. And they like to find the shortest way out. Thus if the pipe branches, the frequency produced will be a function of the shortest path to the exit. I saw this designing base plates for disk drives. If the driving frequency, such as head actuation frequency, was in the neighborhood of a base plate resonance, that resonance was excited. Not wild amounts of math, just Nature's propensity to filter", "timestamp": "1511104955"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911435873082&reply_comment_id=911440104602", "anchor": "fb-911435873082_911440104602", "service": "fb", "text": "→ Re 1: it does matter, but I'm keeping d<<l for all these trials
Re 2: changing the length of paths longer than the shortest path still changes the overall sound. It's not just a shortest path thing.", "timestamp": "1511106141"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272", "anchor": "fb-911440269272", "service": "fb", "text": "I think I understand simple forks now: if you have forks of lengths A and B then the frequency you get is the same as (A+B)/2 would produce.", "timestamp": "1511106224"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "unknown", "source_link": "#", "anchor": "unknown", "service": "unknown", "text": "→ unknown", "timestamp": "-1"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911441242322", "anchor": "fb-911440269272_911441242322", "service": "fb", "text": "→ And it's nothing special about a two way fork: any fork averages it's components. Here's some three way forks that all produce the same note as the final non forked picture:", "timestamp": "1511106614"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911441596612", "anchor": "fb-911440269272_911441596612", "service": "fb", "text": "→ The forks get increasingly breathy and hard to play as the get more imbalanced", "timestamp": "1511106703"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911441646512", "anchor": "fb-911440269272_911441646512", "service": "fb", "text": "→ (these are all ~122hz)", "timestamp": "1511106750"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911442115572", "anchor": "fb-911440269272_911442115572", "service": "fb", "text": "→ I'm curious, does anything change if you blow into a different end of the fork?", "timestamp": "1511107038"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911445139512", "anchor": "fb-911440269272_911445139512", "service": "fb", "text": "→ Sometimes; I'm not sure what the pattern is yet.", "timestamp": "1511108802"}, {"author": "Gawain", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911451576612", "anchor": "fb-911440269272_911451576612", "service": "fb", "text": "→ Another idea: change the diameter of one fork, but keep them both d<<l. I think the pitch will change.", "timestamp": "1511111110"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911440269272&reply_comment_id=911458248242", "anchor": "fb-911440269272_911458248242", "service": "fb", "text": "→ I can't change diameter easily: I just have one size of pipe", "timestamp": "1511113194"}, {"author": "Hollis", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911441626552", "anchor": "fb-911441626552", "service": "fb", "text": "Apparently you've discovered a new way to play the opening of Pachelbel's canon.", "timestamp": "1511106725"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911441626552&reply_comment_id=911441631542", "anchor": "fb-911441626552_911441631542", "service": "fb", "text": "→ Yup!", "timestamp": "1511106737"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911444645502", "anchor": "fb-911444645502", "service": "fb", "text": "Playing more with pre-fork length. It's not consistent. At very short pre-fork lengths it's like the added length is on one of the fork branches, while at very long lengths it's like you just have one long tube:
pre-fork length\tfrequency
0\t94
0.5\t93
1\t92
1.5\t90
2\t87
2.5\t80
3\t73
4\t61
5\t53
This is reconfiguring the same 5ft of piping, from a 2-3 fork with no pre-fork length, down to a 0-0 fork (no fork) with a 5ft pre-fork length.", "timestamp": "1511108415"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911444645502&reply_comment_id=911444979832", "anchor": "fb-911444645502_911444979832", "service": "fb", "text": "→ As wavelength:", "timestamp": "1511108688"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911444645502&reply_comment_id=911445089612", "anchor": "fb-911444645502_911445089612", "service": "fb", "text": "→ It looks like it is piecewise, changing at the point where there's more before the fork than after the fork?", "timestamp": "1511108754"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911444645502&reply_comment_id=911445114562", "anchor": "fb-911444645502_911445114562", "service": "fb", "text": "→ The specific configurations:
3-2 + 0
2.5-2 + .5
2-2 + 1
2-1.5 + 1.5
2-1 + 2
1.5-1.5 + 2
1.5-1 + 2.5
1-1 + 3
0.5 - 0.5 + 4
0-0 + 5", "timestamp": "1511108774"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911483457722", "anchor": "fb-911483457722", "service": "fb", "text": "Playing with stopping a section after a fork: https://docs.google.com/.../1EocCQnyMRtV.../edit...
These are in the form blow -> [left and right]. So 13/7/5 is a blowing into a 13\" pipe, which then forks into a 7\" left pipe and a 5\" right pipe.", "timestamp": "1511124377"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911485897832", "anchor": "fb-911485897832", "service": "fb", "text": "This one doesn't follow the simple fork rule. The top one is happiest at ~83hz while the bottom is happiest at ~99hz.", "timestamp": "1511125302"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911485897832&reply_comment_id=911486262102", "anchor": "fb-911485897832_911486262102", "service": "fb", "text": "→ Some of this is lippable: the top one will go from 70hz to 90hz while the bottom one will go from 76h to 106hz. Which has me worried: how many of my measurements above are off because what felt best was influenced by previous notes I had been playing? Maybe I should always be finding the very highest and very lowest note I can get in a continuous range?", "timestamp": "1511125542"}, {"author": "Michael", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911558033272", "anchor": "fb-911558033272", "service": "fb", "text": "https://usa.yamaha.com/.../casu.../venova/yvs-100/index.html", "timestamp": "1511156484"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911558033272&reply_comment_id=911589779652", "anchor": "fb-911558033272_911589779652", "service": "fb", "text": "→ https://forum.saxontheweb.net/#/topics/252290?page=6", "timestamp": "1511182453"}, {"author": "Jeff Kaufman", "source_link": "https://www.facebook.com/jefftk/posts/911282994452?comment_id=911558033272&reply_comment_id=911589929352", "anchor": "fb-911558033272_911589929352", "service": "fb", "text": "→ Sounds like the \"nose\" makes it overblow an octave, like a flute, instead of a 12th like a clarinet. And:
\"if you cover the \"nose\", the higher octave is only affected a little bit - a change in tone, not really in tuning, but the lower octave drops about a fifth, but no longer lines up with the scale, a lot like the alto recorder I fitted a tenor sax mouthpiece to. The G drops to a C, but the low C drops to about E or Eb, and the higher notes stretch up higher than you might expect - so it goes into clarinet mode, but with the tone holes not lined up right for it.\"", "timestamp": "1511182602"}]}